Give:

f: Z --> R

f(0) = -3

f(1) = f(-1) = 2

f(x) = 0, other wises.

And the kernel K (1/4, 1/2, 1/4).

How can we calculate f*K, where "*" is the convolution operator?

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- September 10th 2007, 06:39 AMle_su14Convolution operator
Give:

f: Z --> R

f(0) = -3

f(1) = f(-1) = 2

f(x) = 0, other wises.

And the kernel K (1/4, 1/2, 1/4).

How can we calculate f*K, where "*" is the convolution operator? - September 10th 2007, 08:32 AMCaptainBlack
- September 10th 2007, 08:58 AMle_su14
So:

The first value: 0*1/4 + 0*1/2 + 2*1/4 = 1/2

The second one: 0*1/4 + 2*1/2 + (-3)*1/4 = 1/4

The third one: 2*1/4 + (-3)*1/2 + 2*1/4 = -1/2

The 4th one: 0*1/4 + 2*1/2 + (-3)*1/4 = 1/4

The last one: 2*1/4 + 0*1/4 + 0*1/2 = 1/2

Is it right? - September 10th 2007, 09:03 AMCaptainBlack