Work / kinetic energy

**^_^Engineer_Adam^_^** · August 25th 2007, 02:47 AM

A baseball pitcher throws a fastball that leaves his hand at a speed of 36.0m/s. The mass of the baseball is 0.145kg. Ignore air resistance. How much work has the pitcher done on the ball in throwing it?

I dunno what to use

$W = \frac{1}{2}m{v_{2}}^2 - \frac{1}{2}m{v_{1}}^2$
help please

the answer is 94.0 Joules

**CaptainBlack** · August 25th 2007, 03:23 AM

Originally Posted by ^_^Engineer_Adam^_^

A baseball pitcher throws a fastball that leaves his hand at a speed of 36.0m/s. The mass of the baseball is 0.145kg. Ignore air resistance. How much work has the pitcher done on the ball in throwing it?

I dunno what to use

$W = \frac{1}{2}m{v_{2}}^2 - \frac{1}{2}m{v_{1}}^2$
help please

the answer is 94.0 Joules

The work done is equal to the change in KE of the ball. In this case the initial
KE is zero (zero speed), and the final KE is $\frac{0.145\times 36^2}{2}$

RonL

Math Help - Work / kinetic energy

LinkBack

Thread Tools

Display

Work / kinetic energy

Similar Math Help Forum Discussions

kinetic energy during energy levels

kinetic energy

kinetic energy

Work-kinetic energy theorem

kinetic energy

Search Tags