# Invert expression to find the Chemical potential of an Ideal Bose Gas

• Feb 27th 2011, 11:26 AM
thelostchild
Invert expression to find the Chemical potential of an Ideal Bose Gas
Hi I'm having trouble with this step of the derivation of the chemical potential for an ideal fermi gas in the low temperature limit

I've got as far as to find
$
E_F = \mu \left(1+\frac{\pi^2}{12} \left(\frac{kT}{\mu}\right)^2 + ...\right)
$

and need to invert this expression to get the chemical potential as a function of fermi energy

I've tried writing this as (which is ok as this is the same as above to first order)
$
E_F = \frac{\mu}{1-\frac{\pi^2}{12} \left(\frac{kT}{\mu}\right)^2}
$

but I cant seem to get it into a form which is easily invertable any chance of a hand here please?

NB the answer I'm trying to get to is
$
\mu = E_F \left(1-\frac{\pi^2}{12} \left(\frac{kT}{E_F}\right)^2 + ...\right)
$
• Feb 27th 2011, 03:11 PM
zzzoak
$
\displaystyle
E=\mu(1+\frac{a}{\mu^2})
$

$
\displaystyle
\mu^2-E\mu+a=0
$

$
\displaystyle
\mu=\frac{E \pm \sqrt{E^2-4a}}{2}=\frac{E \pm E \sqrt{1-4a/E^2}}{2}=
$

$
\displaystyle
=\frac{E \pm E (1-2a/E^2)}{2}=E(1-a/E^2)
$
• Feb 27th 2011, 03:33 PM
thelostchild
ok that makes me feel stupid for not spotting it

Cheers!