That's just the product rule, isn't it?
ok, what if for arguments sake that the function f only depend on x and y then
?
Any how, the original reduces down to
What is happening in the middle terms with the hbar over i moved inside the brackets? It may be a typo as I was writing furiously trying to keep up with the lecturer!
Thanks
Yes.
The hbar over i should distribute and multiply both terms. Your
Any how, the original reduces down to
What is happening in the middle terms with the hbar over i moved inside the brackets? It may be a typo as I was writing furiously trying to keep up with the lecturer!
Thanks
Computing should get you the far left term (minus the test function f).