Taking a partial derivative with respect to a model

**jrobot** · January 10th 2011, 03:56 PM

"[...] These variables give a measure of correspondence between signal ${\bf X}(n)$ and model ${\bf M}_h$ relative to all other models, $h'$ . A mechanism of concept formation and learning, an internal dynamics of the modeling fields (MF) is defined as follows,

${\bf S}_h = {\bf S}_h + \alpha \displaystyle\sum\limits_{n}f(h|n)\left(\frac{\par tial \ln l(n|h)}{\partial {\bf M}_h}\right)\frac{\partial {\bf M}_h}{\partial {\bf S}_h}$

[...]

Parameter $\alpha$ determines the iteration step and speed of convergence of the MF system; $N_h$ can be interpreted as a number of signals ${\bf X}(n)$ associated with or coming from a concept object $n$ . As already mentioned, in the MF internal dynamics, similarity measures are adapted so that their fuzziness is matched to the model uncertainty. [...]"
http://www.leonid-perlovsky.com/4%20-%20Mehler.pdf (page 368)

What does it mean to take a partial derivative with respect to a model ${\bf M}_h$ i.e. $\left(\frac{\partial \ln l(n|h)}{\partial {\bf M}_h}\right)$ ?

Thanks in advance,
jrobot

**emakarov** · January 11th 2011, 10:26 AM

The article says that $l(n\mid h)$ is a contraction for $l(\mathbf{X}(n)\mid\mathbf{M}_h(n))$ , i.e., $l$ is a function of two arguments. So apparently $\frac{\partial \ln l(n|h)}{\partial {\bf M}_h}$ is the derivative with respect to the second argument.

**jrobot** · January 14th 2011, 01:25 PM

I see. Thank you for clearing that up for me.

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