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I want to know what is the different between Laplace transform and Fourier transform?
Can anyone show me? and help me about it?
They have a different kernel. In Laplace, the kernel isOriginally Posted by Hamed
. In Fourier, the kernel is
Also, they are defined over different domains. Laplace is calculated for, where as in Fourier,
.
As Bruno said, please be more specific in what you're asking. These are just a couple of the differences between these two transforms.
For an absolutely integrable real functionwhich is zero for all
, then
(assuming I have done the algebra right and give or take a multiplicative constant due to how the FT is defined)
CB
Your are right!
But I need show diffrent
In wiki I read this :
Can anyone explain it more for me?The Laplace transform is related to the Fourier transform, but whereas the Fourier transform resolves a function or signal into its modes of vibration, the Laplace transform resolves a function into its moments. Like the Fourier transform, the Laplace transform is used for solving differential and integral equations
Exactly what do you not understand in the phrase "the Fourier transform resolves a function or signal into its modes of vibration"?
And the phrase "the Laplace transform resolves a function into its moments" (you can Google for the definition of what the moments of a function are if need be)
Both are of use in differential equations because of the relationship between the FT and LT of a derivative and the function itself, and certain other properties which the two transforms have in common such as the convolution theorems, ...
CB
The Fourier transform gives a representation of a function in terms of a linear supposition of sinusoids, that it analyses the function/signal into vibrational components.
The Laplace transform is related to the moment generating function, and allows the generation of the moments when they exist (in fact they both do).
CB
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