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Math Help - rolling friction

  1. #1
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    rolling friction

    THe coefficient of rolling friction is 0.02, then what force is needed to keep a 5 kg ball rolling at a constant speed on a horizontal surface

    i know to use gravity, 9.8 m/s^2

    please help me with this one.

    thankyou.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by rcmango View Post
    THe coefficient of rolling friction is 0.02, then what force is needed to keep a 5 kg ball rolling at a constant speed on a horizontal surface

    i know to use gravity, 9.8 m/s^2

    please help me with this one.

    thankyou.
    Rolling friction is defined just like kinetic friction:
    f_r = \mu_rN

    -Dan
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by topsquark View Post
    Rolling friction is defined just like kinetic friction:
    f_r = \mu_rN

    -Dan
    i suppose f_r is friction, \mu_r is the coefficient of friction, and N is the force in Newtons? Well, no, they would use F for force right? what do the variables mean?
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Jhevon View Post
    i suppose f_r is friction, \mu_r is the coefficient of friction, and N is the force in Newtons? Well, no, they would use F for force right? what do the variables mean?
    Sorry! I guess I wrote that for only the original poster, didn't I?

    f_r = \mu _r N
    where
    f_r is the force of friction
    \mu _r is the coefficient of rolling friction (typically much less than the coefficient of kinetic friction.)
    and
    N is the normal force on the object between the pair of surfaces inducing the friction.

    -Dan
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