Discrete convolution.

**SanMiguel** · August 20th 2010, 09:57 AM

Could you please check if these are correct. I have done the working out on paper. Thanks.

Y0= -1
Y1= 0
Y2= -1
Y3= 0
Y4= -1
Y5= 0
Y6= 7
Y7= 0
Y8= 0
Y9= 2
Y10= -1
Y11= 0
Y12= -1

All other values of Y are 0.

**yeKciM** · August 20th 2010, 10:54 AM

$y[0] = -1$

$y[1] = 0$

$y[2] = -1$

$y[3] = 0$

$y[4] = -1$

$y[5] = 0$

$y[6] = 7$

$y[7] = 0$

$y[8] = -1$

$y[9] = 0$

$y[10] = -1$

$y[11] = 0$

$y[12] = -1$

**SanMiguel** · August 22nd 2010, 02:35 AM

Yes I see where i went wrong now.

sent you a pm.

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