Hi,

I would like at least some hints to compute the following integral :

$\displaystyle \int_0^\infty exp(-ax) \text{cosh}^{-1/x}(ax) dx $

As a known result we have :

$\displaystyle \lim_{x->0} \text{cosh}^{-1/x}(ax) = 1$

So the function should behave well and be integrable but mathematica gives no anwser for it...

Can somebody help ?

Thanks

Alexis