Hi,
I would like at least some hints to compute the following integral :
$\displaystyle \int_0^\infty exp(-ax) \text{cosh}^{-1/x}(ax) dx $
As a known result we have :
$\displaystyle \lim_{x->0} \text{cosh}^{-1/x}(ax) = 1$
So the function should behave well and be integrable but mathematica gives no anwser for it...
Can somebody help ?
Thanks
Alexis