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Math Help - Inverse Z transform by partial fraction method

  1. #1
    Member moonnightingale's Avatar
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    Inverse Z transform by partial fraction method

    (1 + 2*z + 3*z^2+4*z^3+5*z^4) / z^4

    I have done this question with Difference equation and direct division method and answers come to be
    x(0)= 5
    x(1)= 4
    x(2)=3
    x(3)=2
    x(4)=1
    but i am stuck with partial fraction method.
    Can some body guide me for this
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  2. #2
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    mr fantastic's Avatar
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    Quote Originally Posted by moonnightingale View Post
    (1 + 2*z + 3*z^2+4*z^3+5*z^4) / z^4

    I have done this question with Difference equation and direct division method and answers come to be
    x(0)= 5
    x(1)= 4
    x(2)=3
    x(3)=2
    x(4)=1
    but i am stuck with partial fraction method.
    Can some body guide me for this
    Direct division gives X(Z) = 5 + \frac{4}{z} + \frac{3}{z^2} + \frac{2}{z^3} + \frac{1}{z^4} which are the partial fractions ....
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