# Inverse Z transform by partial fraction method

• July 3rd 2010, 02:53 AM
moonnightingale
Inverse Z transform by partial fraction method
(1 + 2*z + 3*z^2+4*z^3+5*z^4) / z^4

I have done this question with Difference equation and direct division method and answers come to be
x(0)= 5
x(1)= 4
x(2)=3
x(3)=2
x(4)=1
but i am stuck with partial fraction method.
Can some body guide me for this
• July 3rd 2010, 04:50 AM
mr fantastic
Quote:

Originally Posted by moonnightingale
(1 + 2*z + 3*z^2+4*z^3+5*z^4) / z^4

I have done this question with Difference equation and direct division method and answers come to be
x(0)= 5
x(1)= 4
x(2)=3
x(3)=2
x(4)=1
but i am stuck with partial fraction method.
Can some body guide me for this

Direct division gives $X(Z) = 5 + \frac{4}{z} + \frac{3}{z^2} + \frac{2}{z^3} + \frac{1}{z^4}$ which are the partial fractions ....