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Math Help - can i do this using postion vectors?

  1. #1
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    can i do this using postion vectors?

    A jet pilot diving vertically down at 600 km/hr wants to make a quarter turn with-
    out experiencing an acceleration bigger than
    5g. At what minimum height must the turn
    begin? Assume that the speed is constant and that after the quarter turn the plane, moving

    horizontally, is at ground level.

    The solution just quotes a=v^2/R where R is radius of the turn.


    I wondered if could start with r(t)=f(t)i+g(t)j for suitable f,g and then differentiate to find acceleration and so do question?
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  2. #2
    Junior Member allsmiles's Avatar
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    looks good to me!
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  3. #3
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    Quote Originally Posted by allsmiles View Post
    looks good to me!
    any clue as to how?

    im thinking of maybe if t=a is time to reach ground

    r(t)=cos([90-(90t/a))i+sin([90-(90t/a)]j

    with |r(t)|= radius of the circle.


    v(t)=90/a{sin[90-(90t/a)]i-cos[90-(90t/a)]}
    |v(t)|=600

    now im getting confused??
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