
Forming a DE from F=ma
A particle of mass $\displaystyle m$ is projected with speed $\displaystyle u$ along a straight horizontal track. The first section of the track has length $\displaystyle d$. On this section of the track the motion is resisted by a
constant force of magnitude $\displaystyle mk$, where $\displaystyle k$ is a positive constant. The particle does not come to rest on this first section of the track.
Show that the speed $\displaystyle V$ of the particle at the end of the first section of the track is given by:
$\displaystyle V = \sqrt{u^2  2kd}$
Using the equation $\displaystyle ma = F$, I got the following equation.
If we let the speed of the particle = $\displaystyle v$
$\displaystyle m\frac{dv}{dt} = vmk$, however in the solutions they just have $\displaystyle m\frac{dv}{dt} = mk$, what's happened to the $\displaystyle v$, I would have thought that the forces acting on the paticle would be $\displaystyle v$ and $\displaystyle mk$?
Thanks for the help

If you think about your units for a second, $\displaystyle v$ cannot possibly be a force.

Ohh yeh, actually that's rather obvious isn't it :S Think I must be used to dealing with a constant force produced by the engine.
Thanks for spotting that obvious mistake!