Show that the polynomial $\displaystyle p_5$ of deg<=5 such that

x |-2|-1|0|1|2|3|

p(x)|1|4|11|16|13|-4|

That is supposed to be a table with the x's and p(x) values so they just match up like -2 with 1, -1 with 4 etc.

Show it has degree =3 .

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- May 11th 2010, 09:06 AMtn11631Divided difference help?
Show that the polynomial $\displaystyle p_5$ of deg<=5 such that

x |-2|-1|0|1|2|3|

p(x)|1|4|11|16|13|-4|

That is supposed to be a table with the x's and p(x) values so they just match up like -2 with 1, -1 with 4 etc.

Show it has degree =3 .