not very good at physics can someone help me with thit please:
In the absence of air resistance, if a 2 kg ball with potential energy of 144 Joules relative to the floor is dropped, what will it's velocity be just before it hits the floor?
not very good at physics can someone help me with thit please:
In the absence of air resistance, if a 2 kg ball with potential energy of 144 Joules relative to the floor is dropped, what will it's velocity be just before it hits the floor?
Law of Conservation of Energy:
U0 + K0 = U1 + K1
U0 = 144J
K0 = 0
U1 = 0
K1 = ???
144J + 0 = 0 + K1
K1 = 1/2*mv^2 = 144J
v = sqrt(144*2/m) = sqrt(288/2) = 12 m/s
Last edited by ecMathGeek; Apr 24th 2007 at 02:43 PM.