not very good at physics can someone help me with thit please:
In the absence of air resistance, if a 2 kg ball with potential energy of 144 Joules relative to the floor is dropped, what will it's velocity be just before it hits the floor?
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not very good at physics can someone help me with thit please:
In the absence of air resistance, if a 2 kg ball with potential energy of 144 Joules relative to the floor is dropped, what will it's velocity be just before it hits the floor?
Law of Conservation of Energy:Quote:
Originally Posted by rcmango
U0 + K0 = U1 + K1
U0 = 144J
K0 = 0
U1 = 0
K1 = ???
144J + 0 = 0 + K1
K1 = 1/2*mv^2 = 144J
v = sqrt(144*2/m) = sqrt(288/2) = 12 m/s
thankyou for the help on this one.