Originally Posted by
jaspal Suppose a sphere of radius r is dropped into a viscous liquid of coefficient of viscosity q, and its velocity at an instant is v. The frictional force, F, acting against the sphere is given by
F=k(r^x)(q^y)(v^z)
where k is a constant.
Find,using the method of dimensions, the values of x,y,z.
Note the dimensions of the coefficient of viscosity are [M][L]^-1[T]^-1.
My solutions is as follows;
F=ma=[M][L][T]^-2
v=[L][T]^-1
Therefore
[M][L][T]^-2=k[L]^x.q[M]^y.[L]^-y.[T]^-y.[L]^z.[T]^-z