How about the force acting on the car due to its cilcular motion??I'm not too good on circular motion questions so please bare with me , here's my attempt.
Sort a few things out first:
In case we need it later, angular speed,
At the car starts to slip inwards, so this means that the friction is acting up the slope, and that the friction is also equal to where is the normal reaction of the slope on the car?
Resolving vertically I get
Resolving horizontally I get
We can rewrite the second equation as , and substituting in our first equation we get , therefore ?
I have a feeling that Newton's needs to be used but I'm not sure where?
Not sure how to approach the second question either, this has me a bit stumped.
Thanks in advance for the help