haha never mind i figured it out..
When using the three-point formulas for numerical differentiation, specifically for ( )= (1/2h)[-3f( )+4f( +h)-f( +2h)]
and ( )=1/2h[f( +h)-f( -h]
When you have a list of different x and their value at f(x) when you go to plug the formulas in, and you get then you go to how does the formula change? like do all the 's get changed to and so forth? I got my first value done but now im getting stuck on the rest because I don't know what to do with the formula from here.