# Thread: [SOLVED] three-point formula for numerical differentiation

1. ## [SOLVED] three-point formula for numerical differentiation

When using the three-point formulas for numerical differentiation, specifically for $f'$( $x_0$)= (1/2h)[-3f( $x_0$)+4f( $x_0$+h)-f( $x_0$+2h)]

and $f'$( $x_0$)=1/2h[f( $x_0$+h)-f( $x_0$-h]

When you have a list of different x and their value at f(x) when you go to plug the formulas in, and you get $x_0$ then you go to $x_1$ how does the formula change? like do all the $x_0$'s get changed to $x_1$ and so forth? I got my first value done but now im getting stuck on the rest because I don't know what to do with the formula from here.

2. haha never mind i figured it out..