heres a very messy drawing for an idea of what were looking at: http://img89.imageshack.us/img89/1764/untitledyi0.png
area moment of inertia Ix0 of a rectangle about the axis x0 that passes through the centroid is: Ix = 1/12bh^3
the moment of inertia about an axis x that is parallel to the x0 is given by: Ix = Ix0 + Ad^2x
where A is the area of the rectangle, and dx is the distance between the two axes.
the inputs are width w, height h, and thickness t.
w = 200mm h = 300 mm, and t = 22mm
find the moment of inertia:
i know i need to use:
Ix0 = 1/12bh^3
Ix = Ix0 + Ad^2x
i've tried to put this together, but i need some help.
my questions are..
is t the what plugs into b in this problem?
also, is area of the rectangle just Base * height, so 200 * 300?
not sure how to find the distance between the two axis.