Gradient, divergence and curl - nabla crossed with |r|r

**chella182** · November 29th 2009, 11:49 AM

Again, sorry for the naff title.

Find $\nabla\times(r\mathbf{r})$ , where $r=|\mathbf{r}|$ and $\mathbf{r}=(x,y,z)$ .

I ended up with an answer of $(0,0,0)$ , which, again, I doubt is right.

**qmech** · December 1st 2009, 09:54 PM

You're right. A radial field has no curl.

**chella182** · December 2nd 2009, 02:48 AM

Cheers. Yeah, like I said in my other thread, turns out I was doing all of this shizz right when I thought I was doing it wrong

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