Sorry, your friend is right.
. . You forgot about the 20-foot tower . . .
. . x .= .70t
. . . . . . . . . . . . ._
. . y .= .20 + 70√3t - 16tē
Could you please help me to check my answer for the below question? Thanks
A projectile is launch with an initial speed of 140feet per second from a 20 feet tall tower at an angle of pi/3 to the horizontal. Assume that the only force acting on the object is gravity.
Find the maximum horizontal range.
The projectile will reaches its maximum horizontal range when it hit the ground that is when y=0.
so t=0 (ignored) or t= 35sqrt(3)/8
x=70t =70 x 35sqrt(3)/8 = 530.44 ft
So the maximum horizontal range is 530.44ft.
Is my answer correct? The reason I asked that because my friend got a different answer. Her answer is 541.8feet.