physics-static friction + kinetic friction between blocks

I have two masses (m1, m2) stacked on top of each other, then stacked on a table.

m1 is on top of m2 and m1 weighs 5.4kg.

m2 is between m1 and the table and weighs 15.5kg.

the static friction between m1 and m2 is .3 where the kinetic is .1

the static friction between m2 and the table is .5 where as the kinetic is .4

if i apply a horizontal force to the lower block, just enough to make the lower block start sliding.... answer these:

The magnitude of the force: I already solved this.

F-*friction(m1|m2)*static*(m1*g)-*friction(m1+m2|table)*static*(m1+m2)*g=0

F-15.876N-102.41N=0

F-118.286N=0

F=118.286N

Now I need to determine the acceleration fo each block.

I already found the accel for m1:

*friction(m1|m2)*kinetic*m1*g=*Force*m1

*Force*m1=5.292

Force=mass*acceleartion

5.292N=5.4kg*acceleration

acceleration=5.292N/5.4kg

acceleration=.98 meters per second squared

[**Here is where I am stuck**

I need to find the acceleration of m2, but everything I've tried so far has failed. Any ideas?

I can't decide on a final answer here.

Is it going to be

Force(total)-Force(m1+m2|table)-Force(m1|m2)=m2*a (118.286N-81.928N-5.929N=(15.5kg)a

=~1.963-->**[+]**1.96 m/s^2

or

Force(total)-Force(m1+m2|table)-Force(m1|m2)=(m2+m1)*a (118.286N-81.928N-5.929N=(20.9kg)a

=~1.4559->**[ ]**1.46 m/s^2