the inversion laplace transformation of
using the complex inversion formula
i dont understand why s=0 isnt considered a removable singularity, since
s=0 within ln(s^2 + 1) = ln (1) = 0
the lecturer's solutions give s=0 as a simple pole
second question (unrelated to the above problem) concering complex inversion formula problems, with bromich contours
just for verification
considering a function that has 2 branch points (finite points) and a branch cut between the 2 (the cut not extending to infinity) the bromich contour is able to enclose the two branch points and the branch cut, provided you have a second contour scaling just beside and branch cut and around the branch points.
is this correct? do you understand my description?