derive taylor series representation for f(z)=1/1-z for |z-i|<squareroot of 2..ie.. 1/1-z=summation n=0 to infinity (z-i)^n/(1-i)^n+1
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Originally Posted by durham2 derive taylor series representation for f(z)=1/1-z for |z-i|<squareroot of 2..ie.. 1/1-z=summation n=0 to infinity (z-i)^n/(1-i)^n+1 The easy way is to note that: 1. . 2. . Now recall the formula for the sum of an infinite geometric series.
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