Hello. I am having a test coming up soon and am totally lost on how to calculate reactions at given points. In this example I am to solve for Reactions at point A & B.

So the first thing I would do is spit this in half into 2 different shapes, one triangle and one rectangle correct?

If I was to solve for the triangle would I do this:
$force = (2.5 kN/m - 0.5 kN/m) * 3 = 6$

And its location is:
$\frac{3}{3}$ to the right of A?

Is this correct? If not, could someone please explain on how you would approach this question?

Thank you

2. Originally Posted by system32
Hello. I am having a test coming up soon and am totally lost on how to calculate reactions at given points. In this example I am to solve for Reactions at point A & B.

So the first thing I would do is spit this in half into 2 different shapes, one triangle and one rectangle correct?

If I was to solve for the triangle would I do this:
$force = (2.5 kN/m - 0.5 kN/m) * 3 = 6$

And its location is:
$\frac{3}{3}$ to the right of A?

Is this correct? If not, could someone please explain on how you would approach this question?

Thank you
Take moments about A to find the reaction force at B.

The use that the sum of the reactions is equal to the total load to solve for the reaction force at A.

CB