Suppose that f(x) has a zero at x = p and that f'(p) != 0. Show that when f''(p) = 0 Newton's methos converges to p with order at least 3.
Is this solved using a Taylor series expansion. And finding a delta and an M?
-Opps.. f''(p)=0, sp yes, with suitable conditions on the existance and continuity of the third derivative convergence is of order 3 or better.