There is not enough information here to determine the work done without

making some assumptions about what has been omitted from the question.

1. Assume you mean the body hasmassof 1kg

2. Assume the only force acting on the body is one of 5 N, acting for 5s

3. Assume the body starts at rest.

Then we have constant accelleration:

,

so the velocity is:

displacement from initial position is:

Therefore with , , and , we have:

Therefore the work done is the force times the displacement

RonL