Prove the Cauchy-Schwartz inequality |<u, v>| <= |u| |v|. (<= means less than or equal to)

I attempted it a couple times, but didn't get anywhere. Help would be great, thanks.

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- Jun 28th 2009, 03:48 PMFelCauchy-Schwartz Inequality
Prove the Cauchy-Schwartz inequality |<u, v>| <= |u| |v|. (<= means less than or equal to)

I attempted it a couple times, but didn't get anywhere. Help would be great, thanks. - Jun 28th 2009, 04:30 PMarbolis
The complete proof is there : Cauchy?Schwarz inequality - Wikipedia, the free encyclopedia.

- Jun 28th 2009, 04:37 PMFel
I've seen that already, but I couldn't understand it all that well.

- Jun 28th 2009, 05:33 PMBhajun
Please post an attempt at a solution or clarify what you don't understand in the proof provided (preferrably the former).

- Jun 28th 2009, 07:05 PMKrizalid
If then we have the equality, so there's nothing to prove there. Thus let's take care about the interesting case when it's

Under this assumption, put and then

From here we have Hence,