Let G be the group of complex numbers with modulus 1 under multiplication? Is . Justify?

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- June 8th 2009, 12:06 AMChandru1group theory question
Let G be the group of complex numbers with modulus 1 under multiplication? Is . Justify?

- June 8th 2009, 12:36 AMSwlabr
- June 8th 2009, 12:40 AMChandru1Answer
IF V is the vector space then

v \in V may be written as v=w1+w2 where W1 and W2 are subspaces and W1 \cap W2=(0).

Ok.

cant this problem be done by viewing something upon the Kernel. Like if it was isomorphic then K=e..so on - June 8th 2009, 12:58 AMSwlabr
Do you understand how my hint gives you the result?...

Another approach would be to note that and so we can quotient out in both and .

I'm not sure where looking at the Kernel of the isomorphism would really get you. It made me conjour up the above paragraph, but I'm not sure what it would really do. However, in both of my solutions the actual group is irrelevent (as long as it is non-trivial), so I would suspect that there exists a solution that actually uses the group given...

Also, put the text [math-] and [/math-] (without the "-") around your maths to make it LeTeX-ey. - June 8th 2009, 02:09 AMTheAbstractionist
It’s not too hard to see that as follows.

Suppose is a homomorphism. Then since homomorphisms map identities to identities. Hence and so Similarly It follows that maps the four-element set to the two-element set So, what can you conclude here? Can be injective? Can it be an isomorphism?