Originally Posted by

**Jimmy_W** I have become lost.....but in trying to continue with what you provided me with I have come up with the following:

$\displaystyle v= \log x - \frac{<x, \log x>}{<x,x>} \ x.$

$\displaystyle = \log x - \frac{\int_0^1 t \log t \ dt}{\int_0^1 t^2 \ dt}$ $\displaystyle \color{red} (\log x) $

$\displaystyle = \log x - \frac{\int_0^1 t \log t \ dt}{1/3}$ $\displaystyle \color{red} (\log x) $

Am I barking up the wrong tree here? If so, what do I need to do because Ive been trying to figure this out for a while. If not, where do I go from here?

Thanks