Hello,
Leta
-vector space
and
.
Prove thatinvertible
![]()
invertible.
![]()

because of the symmetry, we only need to provelet's show
by
![]()
suppose thatis invertible. then there exists
such that
which gives us:
![]()
multiplying (1) byfrom the left gives us
therefore
because
![]()
thushence:
this shows that
is a right inverse of
this time multilpy (1) byfrom the right to get
and so
because
thus:and hence
i.e.
is also a left inverse of
Q.E.D.

this is true in any ring with unity R, i.e. for any two elementsif the element
is invertible, then
is invertible too and the proof is exactly as i did.
but there's an interesting story behind this. i showed that ifis the inverse of
then
would be the inverse of
professor Tsit Yuen Lam in one
of his books mentions that Kaplansky taught him a way to remember this: sinceis the inverse of
we write:
![]()
(geometric series!) then we'll have:
this is anything but a valid solution. it's actually a completely invalid way which gives a correct answer! Kaplansky just wanted to teach his student a little trick!![]()