What are the root of $\displaystyle x^4-8x^2-8x-2?$ I want precise not with decimals.
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Originally Posted by peteryellow What are the root of $\displaystyle x^4-8x^2-8x-2?$ I want precise not with decimals. $\displaystyle x^4-8x^2-8x-2=x^4-2(2x+1)^2=(x^2-2\sqrt{2}x - \sqrt{2})(x^2+2\sqrt{2}x + \sqrt{2}).$
And you can use the quadratic formula to find zeros of those two quadratic factors.
You'll be lucky becuase I get: 3.2620 -2.1796 -0.6488 -0.4335 as your roots Oops I take that back...........(didnt read the already posted replies duhhh)
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