Hi
It seems not very clear to you ...
Read this and post if you have additional questions
http://www.mathhelpforum.com/math-he...envectors.html
The question is, for which x is the equation valid? And then I am a given a square matrix of say (9 5)(first row) (6 7) (second row.)Then you are given a lambda value of say 4 which apparently is the eigenvalue and . I don't understand the question properly. I can calculate for the eigenvectors since I have the eigenvalue by subtracting them from the diagonal matrix so I will have 9-4 and 7-4 and so on and then I can find the value of x to get the eigenvector. But I don't understand the question properly. I can't multiply the vector by the matrix since it is not a square matrix so, how do you go about it? Thanks all in advance.
Hi
It seems not very clear to you ...
Read this and post if you have additional questions
http://www.mathhelpforum.com/math-he...envectors.html
Thank you gag. I understand the equation and can get the eigenvectors and we are already given the eigenvalue. What I don't understand is just the question which is: for which equation is the valid? We already have lambda which is the eigenvalue, we can get x which is the eigenvector and we have A which is the matrix. This equation is also the same as the det (A - lambdaI)=0. I can calculate for the eigenvectors of both, we already have the eigenvalue so what does for which x is valid mean then?
Thank you. It is just the question and not solving the equation. I know how to get the eigenvalues and eigenvectors but I just didn't get the question: for which x does the equation valid? What does that mean? The matrices I have all have eigen vectors and we are already given their eigen values so, what does for which x (eigenvektor) is the equation valid mean? I think maybe I will try to seek clarification from the teacher but I appreciate your help. Thanks.