Hi , I am doing this linear algebra question:

Find the parametric equations of the line of intersection of the planes x+2z=0 and 2x-3y+4

I don't know whether I am approaching this the correct way or if my answer is correct. What I did was found the cross product of the normals of the vectors which gave me (3,2,-3); then I subbed in zero for x to get 2z=0, -3y=4-> z=0, y=-4/3 and got the equation of the line as being L= (0,0,-4/3)+t(3,2,-3)

Any feedback would be greatly appreciated.