Let A be an m x n matrix, where m<n, then A^t(A) is an n by n matrix. show that det(A^t(A))=0
also if A is a 2 x 3 matrix can you say that det (AA^t)=0
thanks
I'm not the best at Linear Algebra but I'll give this a crack until someone else helps you out.
I'm assuming A^t(A) to mean the transpose matrix of A. So if A is an m x n matrix then the transpose should be n x m, since the rows and columns switch.
Before I try to help, is this what you meant?