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Math Help - quotient Rings 1

  1. #1
    Junior Member
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    quotient Rings 1

    Let R be a ring: since R is an abelian group under +, na has meaning for us for n in Z, a in R. Show that (na)(mb)=(nm)(ab) if n,m are integers and a,b in R.

    Please show steps. Thanks!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mpryal View Post
    Let R be a ring: since R is an abelian group under +, na has meaning for us for n in Z, a in R. Show that (na)(mb)=(nm)(ab) if n,m are integers and a,b in R.

    Please show steps. Thanks!
    you've posted a lot of questions, i can't help but think you want us to do your homework for you

    anyway, use what na and mb means...

    (na)(mb) = \underbrace{(a + a + \cdots + a)}_{n \text{ times}} \underbrace{(b + b + \cdots + b)}_{m \text{ times}} = \cdots

    what does this have to do with quotient rings?
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