Assuming the pi is transcendental over Q, prove that (pi)^2 is also transcendental over Q
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Originally Posted by Coda202 Assuming the pi is transcendental over Q, prove that (pi)^2 is also transcendental over Q If $\displaystyle \pi^2$ was a root of the rational polynomial $\displaystyle P(x)$, then $\displaystyle \pi$ would be a root of $\displaystyle P(x^2)$.
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