Find the equation of the plane through the line (x+1)/2=(y-1)/-1=(z-2)/3 and parallel to the line x/-1=(y+2)/2=(z-3)/-3.

I confess I am stumped and don't know where to start or solve this question.

Can anyone help me?(Headbang)(Angry)

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- Apr 13th 2009, 12:49 AMRobertdekEquation of Plane
Find the equation of the plane through the line (x+1)/2=(y-1)/-1=(z-2)/3 and parallel to the line x/-1=(y+2)/2=(z-3)/-3.

I confess I am stumped and don't know where to start or solve this question.

Can anyone help me?(Headbang)(Angry) - Apr 13th 2009, 03:20 AMPlato
If

is the direction vector of the first line and*u*is the direction of the second line the find $\displaystyle n = u \times v$.*v*

Theis the normal for the plane containing the first line.*n*