(x–1)(x*2 –2x –13) + (2-2x) = (x–1)(x*2 –2x –13) –2(x–1). Does that give you a hint how to continue?
Can someone tell me how to continue from here? I'm stuck
p.s im usiing x for lambda
The matrix of the question is
1 0 -2
-4 -3 2
-1 -2 5
|xI - A| = 0,i get
(x-1) (0) ( 2)
(4) (x+3) -2
(1) (1) (x-5)
Determinant calculation I get
(x-1)(x*2 -2x -13) + (2-2x)
Then I'm stuck here,dont know how to continue.
can someone guide me from here??? The answer i got using the online calculator gave the eigenvalues to be -3,1 & 5.
Pls help..tq...