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Math Help - Eigenvalues

  1. #1
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    Eigenvalues

    Can someone tell me how to continue from here? I'm stuck
    p.s im usiing x for lambda

    The matrix of the question is
    1 0 -2
    -4 -3 2
    -1 -2 5

    |xI - A| = 0,i get

    (x-1) (0) ( 2)
    (4) (x+3) -2
    (1) (1) (x-5)

    Determinant calculation I get
    (x-1)(x*2 -2x -13) + (2-2x)

    Then I'm stuck here,dont know how to continue.
    can someone guide me from here??? The answer i got using the online calculator gave the eigenvalues to be -3,1 & 5.

    Pls help..tq...
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  2. #2
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    Opalg's Avatar
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    (x1)(x*2 2x 13) + (2-2x) = (x1)(x*2 2x 13) 2(x1). Does that give you a hint how to continue?
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  3. #3
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    Thanks a lot man.Managed to solve it, but i keep geting different cvalues for eigenvectors, its half of the original answer.

    Thank you for guiding.
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  4. #4
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    Quote Originally Posted by anderson View Post
    Managed to solve it, but i keep geting different cvalues for eigenvectors, its half of the original answer.
    Hmm, I didn't think to check your original working. There's something wrong at an earlier stage.

    Quote Originally Posted by anderson View Post
    The matrix of the question is
    1 0 -2
    -4 -3 2
    -1 -2 5

    |xI - A| = 0,i get

    (x-1) (0) ( 2)
    (4) (x+3) -2
    (1) (2) (x-5) (You had a 1 there.)
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