How can do we show that the shortest distance between two sets is always the vector that is perpendicular to both sets?
I remembered it went through inner products, but it's not working for me.
So, if i had
<g-f,g-f>= <g,g> - 2 <g,f> + <f,f>
where g,f are column vectors of with n being finite.
I got stuck at that part.
I also rewrote it as
<g-f,g-f>= <g,g>-2*||g||*||f|*cos( |)+<f,f>
But I'm missing something really important.
And out of curiosity, is this true for all vectors? Or is it only true for column vectors?