Can anyone help me with the above problems?
6) this has been proven many times here.. but anyways,
let and assume . show .
Thanks for the reply.
I think the equation in 3 needs multiply signs though.
multiple signs? what the do you mean?
Because (a^m)^n does not equal a^m+a^m+a^m+a^m n times
ahh... yeah.. i mean, ... that should be it.. sorry for that..
and, all you have to do is to remove that + signs..
but anyways, if i assume that the operator is denoted by +, everything should be fine.. it is just a matter of how you denote your operator..
Do you know of an alternative way of doing these proofs without using all the n times sort of things?
It seems a bit ambiguous as it is.
it's the best proof and you will see that proof in many references.. (and i can't think of another for now..)
have you read my notes in the previous post? i edited it..