I am having a hard time factoring the following:

12a^6b^4c^2 + 15a^2b^4c^6

Thanks for the help

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- April 16th 2005, 11:01 PMpinky&thebrainFactoring Question
I am having a hard time factoring the following:

12a^6b^4c^2 + 15a^2b^4c^6

Thanks for the help - April 16th 2005, 11:15 PMbeepnoodle
Are you using carrots ^ to mean multiplication or do you really mean that those are all powers of powers of powers?

- April 17th 2005, 01:29 AMticbol
12a^6b^4c^2 + 15a^2b^4c^6

Rewriting that,

12(a^6)(b^4)(c^2) + 15(a^2)(b^4)(c^6)

If that is the intention, then,

We factor the numerical coefficients first.

12 and 15

There is a factor of 3 that is common to both.

So, (3 )(4 and 5)

Then the variable a.

a^6 and a^2.

There is a factor of a^2 that is common to both.

So, (a^2)(a^4 and 1).

Then the variable b.

b^4 and b^4.

b^4 is common to both.

So, (b^4)(1 and 1).

Then the variable c.

c^2 and c^6.

There is a factor of c^2 that is common to both.

So, (c^2)(1 and c^4)

Hence,

12(a^6)(b^4)(c^2) + 15(a^2)(b^4)(c^6)

= (3*a^2 *b^4 *c^2)(4*a^4*1*1 +5*1*1*c^4)

= (3a^2 b^4 c^2)(4a^4 +5c^4) ....answer.