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Math Help - Normalising vectors - in the complex case

  1. #1
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    Question Normalising vectors - in the complex case

    hi guys,

    Im having difficulty interpreting the norm of vectors with complex entries.( i understand in the real case that to nomalise a vector you sum up the squares of the entries, take the square root of the total and that gives the norm, and the you multiply the original vector by 1/norm to normalise it) but with in terms of dealing with complex entries i don't seem to be getting the right answers, please could you explain why....(please note the vectors are in transposed form)

    1/2(1i, 2, 1+i)

    when normalised gives

    (root2)/4 (1−i, 2 ,1+i) (implying the norm is root 2)

    or if its easier please explain why the normalised version of this vector :
    (i,1−i,−1) is

    1/2(i,1−i,−1)


    thanks so much in advance.


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  2. #2
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    Dec 2007
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    problem solved! realised that u treat an entry like (1-i) for example as root(1^2 +1^2) and 3+2i for example as root(3^2 + 2^2) when normalising
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