# Normalising vectors - in the complex case

• Feb 17th 2009, 03:51 PM
mathlete1
Normalising vectors - in the complex case
hi guys,

Im having difficulty interpreting the norm of vectors with complex entries.( i understand in the real case that to nomalise a vector you sum up the squares of the entries, take the square root of the total and that gives the norm, and the you multiply the original vector by 1/norm to normalise it) but with in terms of dealing with complex entries i don't seem to be getting the right answers, please could you explain why....(please note the vectors are in transposed form)

1/2(1i, 2, 1+i)

when normalised gives

(root2)/4 (1−i, 2 ,1+i) (implying the norm is root 2)

or if its easier please explain why the normalised version of this vector :
(i,1−i,−1) is

1/2(i,1−i,−1)

thanks so much in advance.

• Feb 17th 2009, 06:07 PM
mathlete1
problem solved! realised that u treat an entry like (1-i) for example as root(1^2 +1^2) and 3+2i for example as root(3^2 + 2^2) when normalising