Let S be a subgroup of the group G. Suppose that a, b belongs to G satisfies Sa = bS. Thus the left coset of S containing a equals the right coset of S containing b. Show that Sa = aS = bS = Sb.
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Originally Posted by peteryellow Let S be a subgroup of the group G. Suppose that a, b belongs to G satisfies Sa = bS. Thus the right coset of S containing a equals the left coset of S containing b. Show that Sa = aS = bS = Sb. from we get and for some thus:
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