Find the image of u under the matrix formation f:

f: is a counterclockwise rotation through pi raidans; u = the vector

-2

-3

I started by writing f(u)= cos(2/3 pi) -sin(2/3 pi)

sin(2/3 pi) cos(2/3 pi) * u

f(-2)= -1/2 ......-rad3/2....... -2 = (-1/2)(-2)+(-rad3/2)(-3)

(-3).... rad3/2.... -1/2... .*.. -3... (rad3/2)+(-1/2)(-3)

= (2+3rad3)/2 = 3.59808

= (3-2rad3)/2 = -.23205

My book does not explain how to do this at all. I was actally using the answer to another problem in a solutions manual as a guide. Can anyone confirm if I did this problem right? Thanks!

P.S. I used all the periods to try and space the matrix and vector out since I'm not sure how to type it out correctly.