# Matrix Solution

• Oct 29th 2006, 10:29 AM
JoeDardeno23
Matrix Solution
I have the matrix H:
A11=a+bi
A12=c+di
A21=-c+di
A22=a-bi

I need to show that the equation x^2=-1 has infinitely many solutions in H.
I ignored a (because the book told me to) and so I have the matrix:
A11=bi
A12=c+di
A21=-c+di
A22=-bi
where b^2+c^2+d^2=1.

I'm just having trouble showing the "infinitely many solutions in H" part.
• Oct 29th 2006, 12:15 PM
topsquark
Quote:

Originally Posted by JoeDardeno23
I have the matrix H:
A11=a+bi
A12=c+di
A21=-c+di
A22=a-bi

I need to show that the equation x^2=-1 has infinitely many solutions in H.
I ignored a (because the book told me to) and so I have the matrix:
A11=bi
A12=c+di
A21=-c+di
A22=-bi
where b^2+c^2+d^2=1.

I'm just having trouble showing the "infinitely many solutions in H" part.

You have one constraint on three variables. So, for example, given a value b = 0, how many solutions can you come up with for c and d? I get an infinite number:

$c = cos \theta$ and $d = sin \theta$
where $\theta$ is a continuous parameter.

This alone gives you an infinite number of solutions, but you can obviously make a similar kind of argument for any acceptable value of b, that is for $|b| \leq 1$.

-Dan
• Oct 29th 2006, 04:17 PM
JoeDardeno23
How does this relate back to the matrix though?
• Oct 29th 2006, 06:13 PM
JoeDardeno23
Could someone just explain this subtle point?
• Oct 29th 2006, 06:28 PM
topsquark
Quote:

Originally Posted by JoeDardeno23
Could someone just explain this subtle point?

Your matrix is defined by the values b, c, and d by the A11, A12, A21, and A22 relations that you gave in your initial post. The condition that any matrix belonging to the set H be such that x^2 = -1 gives a constraint on the possibilities that b, c, and d can take, but is not so resistrictive as to give a finite set of possibilities.

-Dan