Hi again, came across this matrix question which has really got me stuck.
A =
1. Find det A, worked this out to be .
2. Show that A is non-singular for all values of q.
If it is non singular, then the det does not equal 0, I think? But how would I go about showing this, solve the quadratic equation in terms of q?
Thanks in advance
I think I've got it, I knew it was completing the square, but wasn't sure why he was doing it exactly. But the is basically saying that whatever number q is, wether it is +ve or -ve,once it is squared and then added to , will always be greater than 0, therefore non singular.
Is this right?
Sorry it took this long to work this rather basic thing out, been revising since 11 this morning, mind just went blank.
Thanks for the help and patience
Yes, that is right. You could also have solve the equation using the quadratic formula and observed that it has two complex roots, no real root.
Sorry it took this long to work this rather basic thing out, been revising since 11 this morning, mind just went blank.
Thanks for the help and patience